In C, strings are null-terminated character arrays. This means the last element of a string array contains ‘/0’. Being arrays, a string variable acts as a pointer to a character (sequence of characters), so array resembles pointer arithmetic . A character array variable name when reference by itself (without any index), points to the first element of the character array, with index number 0.
A library function, say printf (with a format specifier “%s”), expects a character array, and will print out all characters before the first null character ‘0/’. For example:
char charArray[] = {'0/', 'b', 'e', '0/'};
printf("%s", charArray);
The above example will print no character as null is encountered at charArray[0].
printf("%s", charArray + 1);
However, this second example prints “be” because the charArray pointer(base address, which printf(“%s”) expects) is incremented to ‘b’.
Just when I thought I got the relationship between arrays and pointers, I read section 6 of the comp.lang.c FAQ. You should read it too!